from the figure, find the quadrilateral ABCD
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I don't understand your situation.. please batao ki hame isme kya nikalana hhh. perimeter, area etc.
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In Triangle DAB,
A Is a right angle,
Therefore, by pythagorus theorem,
AB^2 + DA^2 = DB^2
12^2 + 9^2 = DB^2
144 + 81 = DB^2
DB^2 = 225
DB = 15cm
Area of triangle DAB = 1/2*12*9
=6*9
= 54cm^2
Now, in area of triangle BDC
= 1/2 * 15 * 3
= 7.5 * 3
= 22.5cm^2
Area of quadrilateral ABCD = Area of traingle DAB + Area of triangle BDC
= 54 + 22.5
= 76.5cm^2
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