From the figure find the value of x,y,z. AC parallel to ED
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Step-by-step explanation:
BE =BD [given]
therefore triangle BED is isoceles
<E=<D [isoceles angle property]
therefore <B+<D+<E=180[angle sum]
50+2<D=180[isoceles angle property]
<D=(180-50)/2=130/2=65
<D=65
<CBD=<D [ alternate interior angle]
<CBD=65
<AEB+<EBD+<CBD=180[ angle sum ]
<AEB+50+65=180
<AEB=180-115
<AEB=65
therefore x=65, y=65 and z=65
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