Question

from the figure given below answer the following​

Answer 1

Pls refer the attachment

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Answer 2

Answer:

AD = 3cm

AD = 3cmCD = 4 cm

Step-by-step explanation:

C is the centre of the circle.

Radius (r) = AC = 5 cm

AB = 6 cm

chord AB ⊥ CD

A perpendicular drawn from the centre of the circle to a chord bisects the chord.

$AD = DB = \frac{1}{2} AB \\ AD = DB = \frac{1}{2} \times 6 \\ AD = DB = \: 3cm$

In △ADC

m∠D = 90°

using Pythagoras theorem,

$AC² = AD² + CD² \\ {5}^{2} = {3}^{2} + {CD}^{2} \\ 25 = 9 + {CD}^{2} \\ {CD}^{2} = 25 - 9 \\ {CD}^{2} = 16 \\ taking \: square \: root \: both \: side \\ CD = 4cm$