Question

From the figure given below. Prove that AB=CD where 'oo is common centre ​

Answer 1

To Prove:

AB = CD

Proof:

First, connect the points of (AO and OD) and (OB an OC)

So that two triangles will be formed,

Now let's use congruent rules,

=> BO = CO (Radius are equal) (of small circle)

=> AO = DO (Radius are equal) (of big circle)

=> ∠AoB = ∠DoC         (In a triangle if two sides are equal its  

                                           corresponding angles are equal)

As per SAS congruency,

ΔAOB congruent to ΔCOD

As per CPCT AB = CD

Hence proved.

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The modified diagram is given below