From the figure of a rectangle given alongside, find the: (1) value of x. (ii) perimeter of the rectangle, (iii) side of a square, whose perimeter is equal to the perimeter of the given rectangle 2x + 5 cm
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i) x = 9cm
ii) Perimeter of Rectangle = 88cm
iii) Side of square = 22cm
Step-by-step explanation:
i) AB = CD
2x + 5 = 4x - 13
2x - 4x = -13 - 5
-2x = -18
x = 9cm
AD = BC
3x - 6 = BC
3(9) - 6 = BC
BC = 21cm
AB = 2x + 5
AB = 2(9) + 5
AB = 23cm
CD = 4x - 13
CD = 4(9) - 13
CD = 23cm
∴ l = 23cm & b = 21cm
ii) Perimeter of Rectangle = 2(l + b)
= 2(23 + 21)
= 2(44)
= 88cm
iii) Side of Square
Perimeter of square = Perimeter of Rectangle
4a = 88
a = 88/4
a = 22cm
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