Question

from the first 50 natural numbers what is the probability of selecting a (1) prime number (2) multiple of 3 (3) multiple of 10 (4) multiple of 4​

Answer 1

Step-by-step explanation:

total no =50

(a) prime number between 1-50= 15

so p(getting prime number)= 15/50=3/10

(b) multiple of 3 Between 50 = 16

so p(getting a multiple of 3)= 16/50 = 8/25

(c) multiple of 10= 5

probability = 5/50= 1/10

(d) multiple of 4= 12

probability= 12/50=6/25

Answer 2

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✿Probability Of Selecting A Prime Number from first 50 natural no:

the primes that are less than 50 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47. There are 15 primes less than or equal to 50. Thus the probability that a prime is selected at random is 15/50 = 30%

✿ From The First 50 natural number Probability Of Multiple Of 3:-

Let A be the event that the number selected is a multiple of 3.

A={3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}

N(a)=16

Probability=

$\frac{number \: of \: favourable \: outcomes}{total \: number \: of \: outcomes}$

$\frac{16}{50}$

Hence, The Probability Is=

$\frac{8}{25}$

✿ From the first 50 Natural Number Probability Of Multiple Of 10

A={10,20,30,40} = n(A)= 4

$\frac{number \: of \: favourabe \: outcomes}{tota l \: number \: of \: outcomes}$

$\frac{4}{50}$

Hence The Probability is=

$\frac{2}{25}$

✿From The First 50 natural Number Probability of multiple of 4

A={4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48} =n(a) =12

$\frac{number \: of \: favourable \: outcomes}{total \: no \: of \: outcomes}$

$\frac{12}{50}$

hence, The probability Is=

$\frac{6}{25}$

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