From the first (675n° +2) natural number, if five consecutive numbers are chosen. E be event that
sum of the numbers is cube of natural number and sum of middle three is a square of a natural number.
then
1
3
(A) P(E)=
ifn=1
(B) P(E)=
if n=1
673
673
E
P(E)=67512 -2
271 +1
71
(C)
for net
(D) P(E)=
675712 -2
for net
Answers
Answered by
2
Answer:
Aree bhai yeh question ki pic daalo yeh aise smjh nhi aara hai
Answered by
0
Answer:
What
is
the
perimeter
of the
parallelogram in the
below image (in
units)?
6b + 2a
9 + 2a
4a
10b
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