From the following diagram calculate ➡
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a) we know
a = dv/dt
= 30/8 = 15/4 = 3.75 m/s^2
b) a(r) = - dv/dt
= - 3.75m/s^2
Total acceleration = 0
While
maximum acceleration = 3.75 m/s^2
c) x(0 to 8) = v.dt = area under graph
= 1/2 x 30 x 8 = 120 m
d) Total distance = 2.120 = 240 m
Answered by
1
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