Question

from the following expressing 3ab,a²,b2,a,5ab,-2ab,2a² the three terms are

Answer 1

Answer:

a2 – b2 = (a – b)(a + b)

(a+b)2 = a2 + 2ab + b2

a2 + b2 = (a – b)2 + 2ab

(a – b)2 = a2– 2ab + b2

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc

(a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc

(a + b)3 = a3+ 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)

(a – b)3 = a3– 3a2b + 3ab2 – b3

a3 – b3 = (a – b)(a2 + ab + b2)

a3 + b3 = (a + b)(a2 – ab + b2)

(a – b)3 = a3– 3a2b + 3ab2 – b3

Answer 2

$\huge\bf{Answer:-}$

Yes

Step-by-step explanation:

Refer the attachment.