from the following figure,find the value of:
I)cot²c-1/sin²c
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here is answer
Step-by-step explanation:
let b is perpendicular to ac at p
then pc=✓12square-4square
pc=8✓2
now, cotsquare c = 8✓2 square/4 square
cotsquare c =128/16 =8
cotsquare c -1= 8-1
=7
sin square c = 4 square/12 square
sin square c = 16/144
sin square c = 1/9
now, cotsquare c-1/sin square c = 7divided by 1/9
=63
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