Math, asked by AnaghaVishnu, 4 months ago

From the following figure , find the values of a) cos A b) cosec A c) tan^2A-sec^2A d) sin C e) sec C f) cot^2C-1/sin^2C​

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Answered by dkchakrabarty01
15

Answer:

first find the value of AB by Pythagoras theorem

AB ^2 = 3^2 + 4^2= 9+16 = 25

AB = 5

cos A = 3/5, cosecA = 5/4, tan^2A - sec^2A = (4/3)^2- (5/3)^2 = 16/9 - 25/9 = -9/9 = -1

Let BD be perp on AC

Calculate DC

DC^2 = BC^2 - BD^2 = 12^2 - 4^2=(12+4)(12-4) =

16×8

Dc = 8√2

sinC = 4/12 = 1/3 you can calculate rest now

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