from the following figure find, x , angleABC and angle ACD.
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Answered by
43
x+4x+4x+3x+48=360
12x=360-48=312
x=312/12=26
Put the value of x you got the answer.
And to find angle ACD
Add the angle in triangle ACD
You get the answer.
In triangle ACD
4x+48+ACD=180
4×26+48+ACD=180
ACD=180-152=28
12x=360-48=312
x=312/12=26
Put the value of x you got the answer.
And to find angle ACD
Add the angle in triangle ACD
You get the answer.
In triangle ACD
4x+48+ACD=180
4×26+48+ACD=180
ACD=180-152=28
MrCombat:
Hiii
Answered by
37
Step-by-step explanation:
find x
A = 48°
B = 4x
C = 3x
D = 4x
x+4x+4x+3x+48°=360°
12x+48°=360°
12x=360°-48°
12x=312
x=312/12=26
Therefore x = 26
find ABC
48°+ 4x+3x=360°
7x+48°=360°
7x=360°-48°
7x=312
x=312/7=104°
Therefore ABC=104°
find ACD
4x+48+ACD=180°
4*26+48+ACD=180°
152+ACD=180°
ACD=180°-152°
ACD=28°
Therefore ACD=28°
Thank You
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