Question

From the following figure, prove that:
AB > CD.
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Answer 1

Answer:

As AB = AC

/_ABC = /_ACB = 70

In triangle ACD

/_ACD = /_CAD + /_ADC

70 = /_CAD + 40

/_CAD = 30

IT MEANS

/_CAD < /_ADC

AC > CD (side opposite to the greatest angle is always greater)

but AB = AC

So, AB > CD

Answer 2

Answer:

this is correct........................