Question

From the following figure, prove that : AB > CD.


Please answer correctly.

Answer 1

Here, we use
axiom 3 which states that equals are subtracted from equals  then the remainders are also equal.

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Solution:

 

Given, AC = BD......(1)



From the figure,
AC = AB + BC 
&

BD = BC + CD

 

On putting these values in eq 1,


⇒ AB +
BC = BC + CD


According to Euclid’s axiom, when equals are
subtracted from equals, remainders are also equal.


On Subtracting BC from  both sides,


AB + BC – BC = BC + CD – BC


AB = CD                 [ by axiom 3 of Euclid]

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Hope this will help you....

Answer 2

HEY

HERE IS ANSWER

Given:-

AB=AC

TO Prove:- AB>CD

Proof: -

in figure

AB=AC .... (1)

in triangle ACD

AC>CD

from equation (1)

since

AB=AC

then

we can write

AB>CD

Hence proved


HOPE IT HELPS

THANKS