Question

From the following options most effective n-bond is :-
(1) 2ри - Зрт
(2) 3dл - 3d
(3) 2ри – 3dл
(4) 3dл - Зрт​

Answer 1

Answer:

I think second is the best option of my according

Answer 2

Explanation:

:

..

N

⊖

=

N

+

=

..

N

−

:⟷:

..

N

..

−

N

+

≡N:⟷:N≡

N

+

−

..

N

..

: out of all these 3, the 1 also called resonance hybrid has exceptional stablization and unique properties.

A destabilizing factor is present in two azides canonical form 2 and 3. each of these 2 structures has 3 bonds, whereas 1 has 4 bonds.

The destablizing resonating structure would want to become stable by welcomig the N≡N as N

2

gas.

Since I is stable, it is less likely to be reactive than 2 and 3 are unstable, therefore would be greater contribution (by being reactive ) compound to I.

hope it will help you