Question

From the following reaction series of reactions
Cl2 + 2KOH → KCl + KCIO + H2O
3KCIO + 2KCl + KC103
4KCIO3 → 3KCIO4 +KCI
Calculate the mass of chlorine needed to produce 100g of KC104​

Answer 1

Answer:

The arrangement of conditions includes;

Cl2+2KOH→KCl+KClO+H2O......(1)

3KClO→2KCl+KClO3 ......(2)

4KClO 3 →3KClO 4 +KCl.......(3)

From the eqn(3)The proportion

KClKClO = 13

Implying that we have 3 moles of KClO3

We have 1mole of KCl

Since the molar mass of KClO4 is 138.55,

We have =

138.55

156

Moles delivered =1.126moles

On the off chance that we accept 100% yield these originated from (1.125× 34) moles of KClO3

=1.501 moles of KClO 3

required to deliver 156g of KClO4

Moles of KClO expected to deliver 1.501 moles of KClO3=1.501×3=4.504 moles of KClO from eqn(2)

From eqn(1)

Moles of Cl2=moles of KClO =4.504 moles.

Along these lines, the mass of Cl 2

=4.504×71

Mass of Cl 2

=319g to deliver 156g of KClO 4

if 100% yield is accepted in the three compound responses.

Hence, this is the answer.

Explanation:

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