Question

From the following thermochemical equation calculate the standard enthalpy of formation of HCL (g).
(A)H2(g)gives 2H(g), ∆H= 436.0kilojoul/mol
(B)cl2(g) gives 2 cl(g),∆H=242.7kilojoulper mol.
(C)HCL(g)+cl(g),∆H=431.8 kilojoule per mole.​

Answer 1

Answer:

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