from the following (v-t) graph find:
(i) distance and displacement in 10 second.
(ii) distance and displacement in 15 second.
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Answers
Answer:
Finding the area under velocity-time graph upto 10 seconds(along with sign) gives the displacement. i think you have not provided the graph as an attachment, but this above information will help you to solve this question by yourself.
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Given:
A velocity-time graph.
To find:
Distance and displacement in 10s.
Distance and displacement in 15s.
Solution:
(i) The distance in 10s can be calculated by determining the area under the graph till 10s. The shape of the graph till 10s is given in the form of a triangle. Hence, we find the area of the triangle to calculate the distance in 10s.
Distance = Area of upper triangle
Distance = × base × height
Distance =
∴ Distance =
Displacement in 10s is given by subtracting the area under the x-axis from the area above the x-axis.
Area above x-axis = Area of upper triangle =
Hence, displacement =
Distance and displacement in 10s are 100m and 100m respectively.
(ii) The distance in 15s can be calculated by determining the area under the graph till 15s. The shape of the graph till 15s is given in the form of two triangles. Hence, we find the area of the triangles to calculate the distance in 15s.
Distance = Area of upper triangle + Area of lower triangle
Distance = × base × height + × base × height
Distance =
Distance =
Displacement in 15s is given by subtracting the area under the x-axis from the area above the x-axis.
Area above x-axis = Area of upper triangle =
Area under x-axis = Area of lower triangle =
Hence, displacement =
Distance and displacement in 15s are 112.5m and 87.5m respectively.
Distance and displacement in 10s are 100m and 100m respectively.
Distance and displacement in 15s are 112.5m and 87.5m respectively.