Question

From the Given ∆ABC, Find the values of
i) sin A
ii) cos A
iii) tan A
iv) sin²A + cos²A​

Answer 1

Answer:

sin A = P/H = 4/5 ( H^2 =P^2+B^2)

cos A = B/H = 3/5

tanA = P/B = 4/3

Sin ^2A + Cos ^2A = (4/5)^2 + (3/5)^2

= 16/25+8/25

= 1

Answer 2

Answer:

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Step-by-step explanation:

by paythagorus formula :CB=4cm

(1) sin A=4/5

(2) cos A=3/5

(3) tan A=4/3

(4) sin^2 A+cos^2 A

=16/25 + 9/25

=16+9/25

=25/25

=1