Question

From the given AP root8,root18,root32....,find the sum of 20terms

Answer 1

Answer:

46√2

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Step-by-step explanation:

1st term = a = √8  = 2√2

2nd term = a + d = √18 = 3√2

so d = 3√2 - 2√2  = √2

3rd term = a + 2d = 2√2 +2*√2 = 4√2 = √32 (data given confirmed)

20th = Last term = L =  a + 19d = 2√2 + 19*√2 = 21√2

Sum = (n/2)(a + L) = (20/10)(2√2 + 21√2)

= 2 * ( 23√2)

= 46√2