From the given diagram,ABC is a Right angled triangle ,right angled at C. Find the height h, the height is drawn to the hypotenuse?
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Let the point of intersection of h and AB be P.
In triangle CPB,
h^2 + 18^2 = BC^2 ... (a)
In triangle ACP, h^2 + 50^2 = AC^2 ... (b)
In triangle ABC,
AB^2 = AC^2 + BC^2
Using a and b
68^2 = h^2 + 50^2 + h^2 + 18^2
4624 = 2h^2 + 2500 + 324
2h^2 = 4624 - 2824 = 1800
h^2 = 900
h = 30 units
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