Question

from the given fig,c=90 degree,ac=12,bc=5 find the value of sin a,cos a,sin² a+cos² a,cosec²a-cot²a​

Answer 1

Answer:

From figure: Δ ABC is a right angled triangle AC2 = BC2 + AB2 AC2 = (5)2 + (12)2 AC2 = 25 + 144 AC2 = 169 = (13)2 or AC = 13 Now from figure, i. cos A = AB/AC = 12/13 ii. cosec A = AC/BC = 13/5 iii. cos C = BC/AC = 5/13 iv. cosec C = AC/AB = 13/12 Hence proved.

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Answer 2

Answer:

13/12 is the correct answer pls mark me as brainlist pls ❤️❤️