Question

from the given figure find all the trigonometric ratios of angle B ab = 40,bc = 41 ac= 9

Answer 1

Hey friend!!!

Here is your answer...

ab=40( base)

bc=41(hypo)

ac=9(perpendicular)

$\sin( \alpha ) = \frac{9}{41} \\ \cos( \alpha ) = \frac{40}{41} \\ \tan( \alpha ) = \frac{9}{40} \\ \cot( \alpha ) = \frac{40}{9} \\ \sec( \alpha ) = \frac{41}{40} \\ \csc( \alpha ) = \frac{41}{9}$

HOPE that it will help you ✌️ ✌️