From the given figure find angle ∠ADC.
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The angel ADC is 45° according to theorem 10.8
Theorem 10m8 says that the angle subtended by an arc at the centre is double the angle subtended by it at any point of the circle
Angle ADC= 1/2 of angle AOC
So angle ADC = 90÷2
angle ADC= 45°
Hope this helps you
mokshithakaza:
Thank you
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