from the given figure find angle opr 'o' is the centre of the circle.
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Answer:
OPR=10°
Step-by-step explanation:
PQR=100°
Then by theorem, angle made by a sector to the centre of a circle is double by the angle made by that sector on the circumference of circle
2PQR=reflexPOR
2×100°=reflexPOR
200°=reflexPOR
Since, POR+reflexPOR=360°
POR+200°=360°
POR=160°
And POR+OPR+PRO=180°
[OPR=PRO as PO=OR]
160°+2OPR=180°
2OPR=20°
OPR=10°
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