from the given figure find the area of the trapezium ABCD given AB=6cm CD=3cm and AD=5cm given ab//dc and ab perpendicular to bc
please help me!! i will mark you as brainliest (only if proper answer)
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Answer:
22.5cm^2=area
Step-by-step explanation:
Side ab is parallel to DC (given)
AD = height (given)
Area=h(sum of parallel sides)/2
=5(6+3)/2
=22.5cm^2
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