Question

FROM THE GIVEN FIGURE , FIND THE LENGTH OF HYPOTENUSE AC AND THE PERIMETER OF TRAINGLE ABC.​

Answer 1

$\huge{\tt{\red{A}\green{N}\purple{S}\pink{W}\blue{E}\orange{R}}}$

${ac}^{2} = \sqrt{ {ab}^{2} + {bc}^{2} }$

${ac}^{2} = \sqrt{ {20}^{2} + {21}^{2} }$

${ac}^{2} = \sqrt{400 + 441}$

${ac}^{2} = \sqrt{841}$

$ac = 29$

$\huge \color{green} \mathfrak{perimeter}$

$p = a + b + \sqrt{ {a}^{2} + {b}^{2} }$

$p = 70$