Question

FROM THE GIVEN FIGURE , FIND THE LENGTH OF HYPOTENUSE AC AND THE PERIMETER OF TRAINGLE ABC.​

Answer 1

Answer:

Ac= 29

Step-by-step explanation:

400+441=841

ac =29

Answer 2

Answer:

AC= 29

Step-by-step explanation:

From the diagram

AB= 20

BC= 21

AC=?

By Pythagoras theorem

AC^2= AB^2 + BC^2

.°. AC^2 = (20)^2 + (21)^2

.°. AC^2 = 400 + 441

.°. AC^2 = 841

.°. AC. = 29 (by taking square root on both side)

.°. AC is 29