Question

From the given figure, find the length of hypotenuse AC and the perimeter of triangle ABC.​

Answer 1

Let AC = x

Then.-

${x}^{2} = {21}^{2} + {20}^{2} \\ {x}^{2} = 441 + 400 \\ {x }^{2} = 841 \\ x = \sqrt{841} \\ x = + - 29$

Answer 2

The length of hypotenuse AC is 29 units

The perimeter of triangle ABC is 70 units

Solution:

By pythagoras theorem, for a right angled triangle ABC,

$AC^2 = AB^2 + BC^2$

From given figure,

AB = 20

BC = 21

Therefore,

$AC^2 = 20^2 + 21^2\\\\AC^2 = 400 + 441\\\\AC^2 = 841\\\\AC = 29$

Thus length of hypotenuse AC is 29 units

Perimeter of triangle ABC

Perimeter = AB + BC + AC

Perimeter = 20 + 21 + 29 = 70

Thus perimeter of triangle ABC is 70 units

Learn more:

The perimeter of triangle is 36 cm and its sides are in ratio a:b:c=3:4:5 then find the side a,b and c

https://brainly.in/question/9137339

Find the perimeter of triangle if one side is 11 centimeters another side IS 1/5 the perimeter and the third side is 1/4 the perimeter

https://brainly.in/question/6092479