Question

from the given figure find the value of
a) BC
b) 2sin B. cos B
c)2 tan B - cos C + 4sin B​

Answer 1

Answer:

a) BD=40

CD=12

BC=BD-CD

BC=40-12=28

Answer 2

(AB)^2=(AD)^2+(BD)^2

(41)^2=(9)^2+{(BC)+(CD)^2}

1681=81+{(BC)+12}^2

{(BC)+12}=√(1600)

BC=40-12

=28

1600=