Question

from the given figure find the value of
a) BC
b) 2sin B. cos B
c)2 tan B - cos C + 4sin B​

Answer 1

Answer:

1. 41^2=9^2+BD^2, BD^2=41^2-9^2=1600, BD=40,BC=40-12=28, 2sinB.cosB=2×(9/41).(40/41)=2×9×40/41^2=720/1681