Question

from the given figure, find the value of tan A + cot C

Answer 1

(ac) ^2=(ab)^2+(bc)^2
169=144+(bc)^2
169-144=(bc)^2
25=(bc)^2
Bc=5

When bc=5
Then
TanA=5/12
Cotc=12/5
Tana+cotc
5/12+12/5
_25+144__
60
169/60

Answer 2

consider triangle ABC, right angled at B
by pythagorus theorem,
AC²=AB²+BC²
13²=12²+BC²
169-144=BC²
BC²=25
BC=5


 SO, tanA =p/b
tanA=BC/AB
tan A= 5/12
cotC= b/p
cotC=5/12

tanA+cotC
5/12+5/12
5+5/12
10/12
10/12 is the answer hope its helps u.......yo