Question

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from the given figure, prove that
ACÍspalal to DE
DB=RC

Answer 1

Answer:

verified

Step-by-step explanation:

in tri abc and bde AC=DE,angle DFE=ABC(90'),and =FE

so,ABC is congruent to DFby cci Ac||Deand DB=RC

Answer 2

in triangle ABC and triangle DEF,

AC= DE(GIVEN)

AB= EF (GIVEN)

ANGLE ABC= ANGLE DFE (90 DEGREE EACH)

THEREFORE, BOTH TRIANGLE ARE CONGRUENT

thus, angle ACB and angle EDF are equal

therefore DE is parallel to AC (alternate interior angels)