From the given figure, prove that the diameter PQ with center O of circle perpendicular to one of the
two parallel chords AB and CD of a circle is perpendicular to the other and bisects both the chords.
Attachments:
Answers
Answered by
2
Step-by-step explanation:
ANSWER
Let AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,
L is mid-point of AB.
OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]
∠ALO=90
o
Similarly, ∠CMO=90
o
Therefore, ∠ALO=∠CMO
But, these are corresponding angles.
So, AB∥CD
Mark answer as brain list
follow me
Similar questions