Question

from the given figure, write down the values of : 1) sin B 2) tanB 3) cos C 4) cot C 5) (sin B cos C + cos B sin C) 6) sec² C - tan² C
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Answer 1

Answer:

Answer:

1. sinB = AC/BC=8/17

2. tanB=AC/AB=8/15

3. cosC=AC/BC=8/17

4. cotC= AC/AB=8/15

5. (sinBcosC+cosBSinC)=8/17×8/17+15/17×15/17

=64/289+225/289=289/289=1

6. (sec^2C-tan^2C)=(17/8)^2-(15/8)^2

=289/64-225/64=64/64=1

Step-by-step explanation: