Question

from the given figure , write down the values of : (1) sin B (2) tan B (3) cos C (4) cot C (5) ( sin B cos C + cos B sin C ) (6) ( sec² C – tan² C)​

Answer 1

Answer:

1. sinB = AC/BC=8/17

2. tanB=AC/AB=8/15

3. cosC=AC/BC=8/17

4. cotC= AC/AB=8/15

5. (sinBcosC+cosBSinC)=8/17×8/17+15/17×15/17

=64/289+225/289=289/289=1

6. (sec^2C-tan^2C)=(17/8)^2-(15/8)^2

=289/64-225/64=64/64=1

HOPE SO THIS MAY HELP U

Answer 2

I HOPE U UNDERSTAND

THANK YOU!