Question

from the given reaction 3 cu + 8HNO3 -cu (no3)2 +2 No +4h2o, calculate the mass copper required to react with 6.3 g hno3​

Answer 1

Answer:

• Mass of HNO₃ = 6.3 g
• Molar mass HNO₃ = 1 + 14 + 16 × 3 = 63 g
• Moles of HNO₃ = 6.3/63 = 0.1 mol

By unitary method:

8 moles of HNO₃ reacts with Cu moles = 3

Therefore, 0.1 mole of HNO₃ reacts with Cu moles = 3/8 × 0.1 = 0.0375 moles

1 mole of Cu has mass = 63.5 g

Therefore, 0.0375 moles of Cu has mass = 63.5 × 0.0375 = 2.38125 g

Answer 2

Answer:

Mass of HNO3 = 6.3 g

Molar mass HNO3 = 1 + 14 + 16 × 3 =

63 g

Moles of HNO3 = 6.3/63 = 0.1 mol

By unitary method:

8 moles of HNO3 reacts with Cu moles 3 =

Therefore, 0.1 mole of HNO3 reacts

Cu moles = 3/8 × 0.1 = 0.0375 moles

with

1 mole of Cu has mass = 63.5 g

Therefore, 0.0375 moles of Cu has mass = 63.5 x 0.0375 = 2.38125 g