Question

from the given table answer the following :please give me answer as soon as possible....​

Answer 1

Electrons present in e are : 4

C is a inhert gas because it has completely full electrons in it's outermost shell

Atom b will form negative ion

Element d has 12 neutrons as atomic mass = no. of protons + no. of neutrons

And no. of protons = no. of electrons

23= 11- no. of neutrons

= 12

Answer 2

A). Electrons present in E.

Mass no. = 9

Atomic no. = 4

Thus, atomic no. = Mass no. - no. of neutrons

4 = 9 - no. of neutron

No. of neutron = 9-4=5

Therefore,

Proton + neutron = mass no

Proton + 5=9

Proton= 4

This no.of electron = no.of proton =4

B) c is an inert gas because it has atomic no. 2 and has valency 0. Those elements having valency 0 are inert gas

C). B will form negative charged ions because it has electronic configuration 2,7 as it's atomic no. is 9. Thus to complete it's shell it needs one electron . Thus gaining of electron forms negative charge.

D). D has 12 neutrons because

Atomic no. = Mass no. - no. of neutrons

D= 23-11=12

E). D will form a positive charge as it has electronic configuration 2,8,1 because of its atomic no. 11. Thus to complete it's shell it will loose 1 electron which makes it positively charged.