Question

From the ideal gas equation we get PV=nRT.....What is the dimention of R?what is its value?????

Answer 1

 Unit of gas constant in terms of Joules
When,
R = PVnTPVnT

In CGS units, the unit of pressure is dyne cm-2 and volume is cm3 mol-1. Then,
Standard temperature T = 273.15 KStandard pressure, P = (1 x 76 x 13.6 x 981) dyne cm-2Molar volume under standard temperature and pressure = 22414 cm3mol-1
Therefore,

R = 76 X 13.6 X 981 X 22414273.1576 X 13.6 X 981 X 22414273.15 erg deg-1 mol-1

= 8.314 x 107 erg deg-1 mol-1

Since, 4.182 x 107erg = 1calorie

Hence,

R = 8.314 X 107 erg deg−1 mol−1
4.182 X 107 erg cal−18.314 X 107 erg deg−1 mol−14.182 X 107 erg cal−1 = 1.987 cal deg-1 mol-1

Answer 2

 Unit of gas constant in terms of Joules
When,
R = PVnTPVnT

In CGS units, the unit of pressure is dyne cm-2 and volume is cm3 mol-1. Then,
Standard temperature T = 273.15 KStandard pressure, P = (1 x 76 x 13.6 x 981) dyne cm-2Molar volume under standard temperature and pressure = 22414 cm3mol-1
Therefore,

R = 76 X 13.6 X 981 X 22414273.1576 X 13.6 X 981 X 22414273.15 erg deg-1 mol-1

= 8.314 x 107 erg deg-1 mol-1
Since, 4.182 x 107erg = 1calorie

Hence,

R = 8.314 X 107 erg deg−1 mol−1
4.182 X 107 erg cal−18.314 X 107 erg deg−1 mol−14.182 X 107 erg cal−1 = 1.987 cal deg-1 mol-1

Read more on Brainly.in - https://brainly.in/question/2858055#readmore
Please mark as brainliest