From the information given in figure, prove that ∆ABC ≅ ∆DCB
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Answer:
(i). A ABC = A DCB.------- (ii) Hence AC = DB ..(S.A.S. Axiom) ..(c.p.c.t.)
Step-by-step explanation:
Proof:
In A ABC and A DCB,
CB = CB---------------------(common)
ZA BC = Z BCD -----------(each 90°)
and AB = CD -------------------.(given)
(i). A ABC = A DCB.... (ii) Hence AC = DB ..(S.A.S. Axiom) ..(c.p.c.t.)
Hence proved.
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