Question

From the information given in the figure, find PR and PQ. In △PQR, ∠Q = 90°, ∠P = 60°, and ∠R = 30°. By the theorem of 30° - 60° - 90° triangle,​

Answer 1

Answer:

In △PQR, ∠P=300,∠Q=600,∠R=900 and PQ=10

sin60=PQPR ( sinθ=HypotenusePerpendicular)

23=10PR

PR=53 cm

cos60=PQQR ( cosθ=HypotenuseBase)

21=10QR

QR=5 cm