Question

from the length of the tangent drawn from a point, whose distance from the centre of a circle is 17cm and radius is 8 cm

Answer 1

let AB be the tangent,BO be the radius and distance of point A from o centre is 17 cm and radius BO is 8 cm . we know that tangent of a circle is perpendicular to radius of circle by theorem. then angle ABO is 90° . by Pythagoras theorem , AO^2= BO^)2+ AB^)2. so 17^2= AB^2+8^2. so 289-64=AB^2=225. so AB=15cm = length of tangent

Answer 2

Answer:

Let p be the given point , o be the centre of the circle and PT be the length of tangent from p

Then OP = 17 cm

OT = 8cm

since tangent to a circle is always perpendicular to the radius through the point of contact

Therefore angle OTP = 90°

In right triangle OTP we have ,

op2 = OT2 + PT2

17square = 8 square + PT square

289 = 64 + PT square

PT square = 289- 64

PT square = 225

PT =√225

PT = 15 cm

Hence the length of tangent from P = 15cm