Question

From the lesson; motion

An object moves 6km due to west and then 8km due to North. Find the distance covered by the object and it's displacement.

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Answer 1

Answer:

Distance depends on the path. So if the points are o, w, n….then ‘o’ to west ‘w’ that is ‘ow’ = 6 km and like that’w’ to ‘n’ “wn”=8 km

Now the distance will be the total of (‘ow’+‘wn’)= 6+8= 14 km

But displacement does not depend on the path the body passes, instead it depends on initial and ending point..

If we consume a triangle connecting the point o, w, n… then it will be an equiangular triangle… and the initial point of movement of that body is ‘o’ and and the ending point is ‘n’

So the displacement of the body will be ‘o’ to ’n’ that is ‘on’ which is hypotenuse of the equitrianglur triangle.. now to get the value of ‘on’ u have to apply ‘Pythagoras theorum—

on^2=ow^2+wn^2=6^2+8^2=36+64=100

on^2=100

Therefore on=10km (Displacement)

Answer 2

Answer

Distance , D = 14 km

Displacement , d = 10 km

Given

• An object moves 6 km due to west and then 8 km due to North

To Find

• Distance and Displacement

Solution

8 km

North

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West  <-_ _ _ _ _ _ _ _ _ _ _ _ _  6 km

Distance is defined as , " The total ground covered by an object "

⇒ Distance , D = 6 km due west + 8 km due North

⇒ D = 6 km + 8 km

⇒ D = 14 km

So , Distance is 14 km

Displacement is defined as , " shortest distance b/w two points "

So , Apply Pythagoras theorem to find displacement , d.

⇒ d² = 6² + 8²

⇒ d² = 36 + 64

⇒ d² = 100

⇒ d = 10 m

So , Displacement is 10 m