from the mixture of 2 moles of ca3(po4)2 and 3 moles of na2so4 and 1 mole of c3o2 sll the oxygen atoms are removed then moles of o3 molecule formed from all these atoms are
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For the 1 mole of Ca3(PO2)2 and P4O10, we have 2 and 4 mole of P atoms respectively. Hence, for the 2 moles of the Ca3(PO2)2 and 5 moles of P4O10 will have 2* 2 = 4 mole and 5*2 = 10 mole of Phosphorus atoms respectively.
Similarly, for the 6 mole of H3PO4, it will have 6 * 1 = 6 mole of Phosphorus atoms.
Therefore, the total moles of Phosphorus atoms present will be = 8 + 20 + 6 = 34 Phosphorus atoms.
So, 34 P atoms will be present in the 34/2 = 12.5 Phosphorus(4P4) molecules.
So, the moles of P4 will be = 12.5/6.023 * 10^23 = 2.075* 10^-23 moles of P4.
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