Question

FROM the numbers 1, 2, 3 , one number x is selected and from the numbers 1, 4, 9 second number y is selected . Find the probability that the
(a) product of two numbers is less than 9.
(b) product of two numbers is more than 13
(c) sum of two numbers is 12

Answer 1

a)sum of all no. are1,2,3,1,4,9-20
Total digits less than 9 -5
P(product of no. less than 9)
-5/20 -1/4
b) 2/20 - 1/10
c) 1/20

Answer 2

Answer:

Total outcomes : 6

{1,1};{1,4};{1,9}

{2,1};{2,4};{2,9}

{3,1};{3,4};{3,9}

a) product of two numbers is less than 9.

Favorable outcomes = {1,1};{1,4};{2,1};{2,4};{3,1} =5

So, probability that the  product of two numbers is less than 9. = $\frac{5}{6}$

b)product of two numbers is more than 13

Favorable outcomes={2,9};{3,9}=2

So, probability that the product of two numbers is more than 13= $\frac{2}{6}$

                                                                                                         = $\frac{1}{3}$

c)sum of two numbers is 12

Favorable outcomes= {3,9}

So, probability that the sum of two numbers is 12 = $\frac{1}{6}$