From the point 15 m away from the foot of the pole of height 50 m the angle of elevation to the top pole is____
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Step-by-step explanation:
Given, BC is 15 and angle of elevation on ground is 30
0
Let the height of the pole be h
In right angled ΔABC.
tan30
0
= BCAB
3
1= 15h
∴h= 3
15
∴h=5
3 feet solution
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