From the point 15m away from the foot of the pole of height 50m the angle of elevation to the top of the pole is
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Let the height of the pole be h and the distance between the pole and tower be x.
It can be observed that,
tan60
∘
=
x
50
3
=
x
50
x=
3
50
And,
tan45
∘
=
x
50−h
1=
x
50−h
50−h=x
50−h=
3
50
h=50−
3
50
h=
3
50(
3
−1)
h=21.1m
Therefore, the height of the pole is 21.1m.
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