Question

from the point Q the length of the tangent to a circle is 24cm and the distance of Q from the centre is 25cm find the radius of the circle

Answer 1

Hii... Your answer
In triangle OPQ
By pythagoras theorem....
$( {oq})^{2} = ( {op})^{2} + ( {pq})^{2} \\ ( {25})^{2} = ( {op})^{2} + ( {24})^{2} \\ ( {op})^{2} = ( {25})^{2} - ( {24})^{2} \\ ( {op})^{2} = (25 + 24)(25 - 24) \\ ( {op})^{2} =( 49)(1) \\ ( {op})^{2} = 49 \\ op = \sqrt{49} \\ op = 7cm$
The radius of the circle is 7cm

Answer 2

From a point q the length of the tangent to a circle is 24cm and the distance of q from the centre is 25cm .The radius of the circle is A.7cm B.12cm C.15cm D.24.5cm