Math, asked by 8ayashvibhat, 26 days ago

from the product of (-4/7x²y) and (-2/3y²z³) subtract the product of (-3/7xy²z) and (5xyz²) ​

Answers

Answered by shreekrishna35pdv8u8
2

Answer:

Step-by-step explanation:

(-4/7x²y) × (-2/3y²z³)

= -4/7* -2/3 x²y¹+² z³

= 8/21 x²y³z³

(-3/7xy²z) × (5xyz²) ​

= -3/7 * 5 x¹+¹ y²+¹ z¹+²

= -15/7 x²y³z³

8/21 x²y³z³ - ( -15/7 x²y³z³)

= 8/21 x²y³z³ + 15/7 x²y³z³

= 8+45 /21 x²y³z³

= 53/21 x²y³z³

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