Question

From the quadratic equation whose root are 3/4 and -2/3​

Answer 1

Answer:

Sum of zeroes = 3/4 -2/3

= (9-8)/12

=1/12

Product of zeroes = 3/4 × -2/3

= -6/12 = -1/2

Quadratic eq is

x^2 -(sum of zeroes)x + product of zeroes

= x^2 - x/12 -1/2

=12x^2 - x -6

Answer 2

Concept Introduction:-

It could take the shape of a word or a numerical representation of a quantity's arithmetic value.

Given Information:-

We have been given that root are $3/4$ and $-2/3$

To Find:-

We have to find that from the quadratic equation whose root are $3/4$ and $-2/3$

Solution:-

According to the problem

The roots of the equation are,  $3/4$ and $-2/3$

$\left(x-\frac{3}{4}\right)\left(x-\frac{-2}{3}\right)=0\\\left(x-\frac{3}{4}\right)\left(x+\frac{2}{3}\right)=0\\x^{2}+\frac{2}{3} x-\frac{3}{4} x+\left(\frac{-2}{3}\right)\left(\frac{3}{4}\right)=0\\x^{2}-\frac{x}{12}-\frac{1}{2}=0\\\therefore 12 x^{2}-x-6=0$

Final Answer:-

The correct answer is $12 x^{2}-x-6=0$.

#SPJ3